Question

How do you solve `-9*e^(3-6r)=-3`?

Answer 1

I found: `r=1/6{3-ln[1/3]}=0,6831`

Explanation:

Let us try rearranging it:
`e^(3-6r)=(-3)/(-9)`
I took the `-9` to the right:
we get:
`e^(3-6r)=1/3`
Take the natural log of both sides:
`ln[e^(3-6r)]=ln[1/3]`
we get:
`3-6r=ln[1/3]`
`6r=3-ln[1/3]`
`r=1/6{3-ln[1/3]}`
if you can use a scientific calculator you'd get:
`r=1/6{3-ln[1/3]}=0,6831`