How do you solve #9\leq 4x - 7#?

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Answer 1 · 2017-09-27T20:29:44

# x >= 4#

#9 <= 4x -7#
Flip the equation
#4x - 7>=9#
#4x >=9+7#
#4x>+16#
Divide both sides by #color(red)(4)#
#(4x)/color(red)(4) >= 16/color(red)(4)#
#x >= 4#

Answer 2 · 2017-09-27T20:31:08

#x>=4#

Add 7 to both sides

#16<=4x#

And divide through by 4

#4<=x#