How do you solve #9^ { x } = 27^ { x - 2} #?
1 Answer
Jun 11, 2017
Explanation:
#"change the "color(blue)"base "" from " 9 to 3#
#rArr(3^2)^x=(3^3)^(x-2)#
#rArr3^(2x)=3^(3x-6)#
#"since the bases are the same, we can equate the exponents"#
#rArr3x-6=2x#
#rArrx=6#
