How do you solve #9^x=3^(x+4)#?

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Answer 1 · 2018-04-16T14:18:08

#x=4#

Given: #9^x=3^(x+4)#

Notice that #9=3^2#. So, we get:

#=>(3^2)^x=3^(x+4)#

Using the fact that #(a^b)^n=a^(bn)#, we get:

#=>3^(2x)=3^(x+4)#

The bases are equal, so we can say that:

#2x=x+4#

#2x-x=4#

#x=4#