How do you solve #-9| x + 8| + 4\leq - 5#?

1 Answer
Oct 1, 2017

Solutions:

#x>=-7#

#x<=-9#

Explanation:

Solve:

#-9abs(x+8)+4<=-5#

Subtract #4# from both sides.

#-9abs(x+8)<=-5-4#

Simplify.

#-9abs(x+8)<=-9#

Divide both sides by #-9#. This will reverse the inequality.

#(color(red)cancel(color(black)(-9))^1abs(x+8))/color(red)cancel(color(black)(-9))^1>=color(red)cancel(color(black)(-9))^1/color(red)cancel(color(black)(-9))^1#

Simplify.

#abs(x+8)>=1#

Since #absa=+-a#, we can break the equation into two equations:

#x+8>=1# and #-(x+8)>=1#

Solve the first equation: #x+8>=1#.

Subtract #8# from both sides.

#x>=1-8#

Simplify.

#x>=-7#

Solve the second equation: #-(x+8)>=1#.

#-x-8>=1#

Add #8# to both sides.

#-x>=1+8#

Simplify.

#-x>=9#

Multiply both sides by #-1#. This will reverse the inequality.

#x>=9xx-1#

#x<=-9#

Solutions:

#x>=-7#

#x<=-9#