How do you solve #9a + 5= 3a - 1#?

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Answer 1 · 2016-11-01T21:54:01

#a = -1#

Solve for #a# keeping the equation balanced:

#9a + 5 - 3a - 5 = 3a - 1 - 3a - 5#

#(9a - 3a) + (5 - 5) = (3a - 31) - (1 + 5)#

#6a + 0 = 0 - 6#

#6a = -6#

#(6a) / 6 = -6/6#

#a = -1#