How do you solve #9r + 3\leq - 15#?

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Answer 1 · 2018-03-26T01:14:53

See a solution process below:

First, subtract #color(red)(3)# from each side of the equation to isolate the #r# term while keeping the inequality balanced:

#9r + 3 - color(red)(3) <= -15 - color(red)(3)#

#9r + 0 <= -18#

#9r <= -18#

Now, divide both sides of the inequality by #color(red)(9)# to solve for #r# while keeping the inequality balanced:

#(9r)/color(red)(9) <= -18/color(red)(9)#

#(color(red)(cancel(color(black)(9)))r)/cancel(color(red)(9)) <= -2#

#r <= -2#