How do you solve #9v + 7< 10v - 4#?

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Answer 1 · 2017-11-27T20:19:17

#v>11#

#9v + 7<10v-4#

So let's start subtracting #color(red)(10v)# from both sides

#9v + 7 color(red)(-10v) < cancel(10v) - 4 cancelcolor(red)(-10v)#

#-v + 7 < -4#

Then subtract #color(green)(7)# from both sides

#-v cancel(+7) cancelcolor(green)(-7) < -4 color(green)(-7)#

#-v < -11#

Now remember that we cannot leave the variable with a negative sign. There are two ways to remove a negative sign in front of a variable.

1) You can divide both sides by #color(red)(-1)#
2) You can multiply both sides by #color(red)(-1)#

So, let's divide both sides #color(red)(-1)#

#(-v)/(-1)<(-11)/(-1)#

When divide by negative sign, we need to change the sign. So it was #<#, now it will be #>#

Thus, the answer is

#v>11#