How do you solve #9x ^ { 2} - 5= 121#?

1 Answer
Jan 28, 2017

See the entire solution process below:

Explanation:

First, add #color(red)(5)# to each side of the equation to isolate the #x# term while keeping the equation balanced:

#9x^2 - 5 + color(red)(5) = 121 + color(red)(5)#

#9x^2 - 0 = 126#

#9x^2 = 126#

Next, divide each side of the equation by #color(red)(9)# to isolate the #x^2# term while keeping the equation balanced:

#(9x^2)/color(red)(9) = 126/color(red)(9)#

#(color(red)(cancel(color(black)(9)))x^2)/cancel(color(red)(9)) = 14#

#x^2 = 14#

Now, take the square root of each side of the equation to solve for #x# while keeping the equation balanced. Remembering, the square root of a number can be either #+# or #-# the number:

#sqrt(x^2) = +-sqrt(14)#

#x = +-sqrt(14) = +-3.74# rounded to the nearest hundredth.