How do you solve #9x - ( 2x + 3) + 11= 3x#?

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Answer 1 · 2017-06-15T03:00:55

See a solution process below:

First, on the left side of the equation remove the terms from parenthesis, group and combine like terms:

#9x - 2x - 3 + 11 = 3x#

#(9 - 2)x + (-3 + 11) = 3x#

#7x + 8 = 3x#

Next, subtract #color(red)(8)# and #color(blue)(3x)# from each side of the equation to isolate the #x# term while keeping the equation balanced:

#-color(blue)(3x) + 7x + 8 - color(red)(8) = -color(blue)(3x) + 3x - color(red)(8)#

#(-color(blue)(3) + 7)x + 0 = 0 - 8#

#4x = -8#

Now, divide each side of the equation by #color(red)(4)# to solve for #x# while keeping the equation balanced:

#(4x)/color(red)(4) = -8/color(red)(4)#

#(color(red)(cancel(color(black)(4)))x)/cancel(color(red)(4)) = -2#

#x = -2#