How do you solve #9x + 3 = 3x + 27#?

1 Answer
Mar 31, 2016

#x=4#

Explanation:

The trick with these is to rigidly stick to the rule that
#color(red)("what you do to one side of the equation you do to the other.")#

#color(green)("The short cuts use this rule but they miss out stages.")#
'~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
#color(blue)("Using first principles")#

Given:#" "color(brown)(9x+3=3x+27)#

Subtract #color(blue)(3)# from both sides

#color(brown)(9x+3color(blue)(-3)" "=" "3x+27color(blue)(-3))#

#color(brown)(9x+0" "=" "3x+24)#

'~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
Subtract #color(blue)(3x)# from both sides

#color(brown)(9xcolor(blue)(-3x)" "=" "3xcolor(blue)(-3x)+24)#

#color(brown)(6x" "=" "0+24)#
'~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
Divide both sides by #color(blue)(6)#

#color(brown)(6/(color(blue)(6))x" "=" "24/(color(blue)(6)))#

But #6/6=1" and "24/6=4#

#1xx x=4#

But the correct way to write #1xx x" is just "x" on its own"#

#x=4#