How do you solve #(a+4)/2 = (a+4)/a#?
By first cross-multiplying 7 then trasposing, the eqn. becomes,
a(a+4)-2(a+4)=0, i.e., (a+4)(a-2)=0.
Hence the soln. : a=-4, a=2.
As the top values (numerators) are of the same value we could disregard them and simply write
However, I suspect the that question poser is looking for you to use algebraic manipulation. So hear goes!
Invert both sides giving:
Multiply both sides by