How do you solve #A+6\times 21\leq 15#?

1 Answer
Nov 9, 2017

See a solution process below:

Explanation:

Use the standard order of operation or PEDMAS, we can multiply the two terms on the left side of the inequality giving:

#A + 126 <= 15#

Now, subtract #color(red)(126)# from each side of the inequality to solve for #A# while keeping the inequality balanced:

#A + 126 - color(red)(126) <= 15 - color(red)(126)#

#A + 0 <= -111#

#A <= -111#