How do you solve #a/7-4=2#?

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Answer 1 · 2016-07-19T02:04:13

#color(magenta)("a=42")#

#color(coral)("Add 4 to both sides:")#

#a/7-4=2#
#color(white)(aa) +4 +4#

Four cancels out on the left side, and when you add 2+4 on the right side you obtain 6:

#a/7=6#

#color(magenta)("Multiply both sides 7 to remove the denominator,")##color(magenta)("doing this will get a by itself:")#

#a/cancel7xxcancel7=6xx7#

Now you are just left with #a# on the left side and 42 on the right side.

Thus,
#color(blue)"a=42"#