# How do you solve abs(10+x)<=13?

Apr 15, 2017

$- 23 \le x \le 3$

#### Explanation:

Inequalities of the type $| x | \le a$ always have solutions of the form.

$- a \le x \le a$

$\Rightarrow - 13 \le 10 + x \le 13$

Isolate x in the centre interval by subtracting 10 from ALL 3 intervals.

$- 13 - 10 \le \cancel{10} \cancel{- 10} + x \le 13 - 10$

$\Rightarrow - 23 \le x \le 3 \text{ is the solution}$