How do you solve #abs(12-x)<=19#?

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Answer 1 · 2016-10-15T11:41:39

#x in [-7,+27]#

If #abws(12-x)<=19#
then

#{: (12-x <=19,color(white)("XX")andcolor(white)("XX"),12-x >=-19), (rarr -x <= 7,,rarr-x>=-27), (rarr x>=-7,,rarr x<=27) :}#

Answer 2 · 2016-10-15T11:47:18

#x<=31# or #x>=-7#

#∣12-x∣<=19 #
#12-x<=19# or ##-(12-x)<=19 #x>=-7# or #x<=31#