How do you solve #abs(12-x)<=19#?

2 Answers
Oct 15, 2016

Answer:

#x in [-7,+27]#

Explanation:

If #abws(12-x)<=19#
then

#{: (12-x <=19,color(white)("XX")andcolor(white)("XX"),12-x >=-19), (rarr -x <= 7,,rarr-x>=-27), (rarr x>=-7,,rarr x<=27) :}#

Oct 15, 2016

Answer:

#x<=31# or #x>=-7#

Explanation:

#∣12-x∣<=19 #
#12-x<=19# or ##-(12-x)<=19 #x>=-7# or #x<=31#