# How do you solve abs(16-x)>=10?

Solution: $x \le 6 \mathmr{and} x \ge 26$ . In interval notation $\left(- \infty , 6\right] \cup \left[26 , \infty\right)$
$| 16 - x | \ge 10 \mathmr{and} 16 - x \ge 10 \mathmr{and} - x \ge - 6 \mathmr{and} x \le 6$ OR
$| 16 - x | \ge 10 \mathmr{and} 16 - x \le - 10 \mathmr{and} - x \le - 26 \mathmr{and} x \ge 26$
Solution: $x \le 6 \mathmr{and} x \ge 26$ . In interval notation $\left(- \infty , 6\right] \cup \left[26 , \infty\right)$ [Ans]