How do you solve #abs(2x+1) >1#?

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Answer 1 · 2018-05-22T13:00:17

The solutions are #x in (-oo,-1) uu(0, +oo)#

This is an inequality with absolute values

#|2x+1|>1#

The solution is

#{(2x+1>1),(-2x-1>1):}#

#{(2x>0),(-2x>2):}#

#{(x>0),(x<-1):}#

The solutions are #x in (-oo,-1) uu(0, +oo)#

graph{|2x+1|-1 [-6.24, 6.244, -3.12, 3.12]}