How do you solve #abs(2x-3)<=3#?
1 Answer
Apr 11, 2018
Explanation:
#"inequalities of the type "|x|<=a#
#"always have solutions of the form"#
#-a<=x<=a#
#rArr-3<=2x-3<=3#
#"add 3 to each interval"#
#cancel(-3)cancel(+3)<=2xcancel(-3)cancel(+3)<=3+3#
#rArr0<=2x<=6#
#"divide each interval by 2"#
#rArr0<=x<=3" is the solution"#
#x in[0,3]larrcolor(blue)"in interval notation"#
