How do you solve abs(2x-3)>5? Algebra Linear Inequalities and Absolute Value Absolute Value Inequalities 1 Answer jk.13 Apr 4, 2018 x>4 OR x<1 Explanation: Set up two different possibilities. 2x-3>5 OR -2x+3>5 2x>8 OR -2x>2 x>4 OR x<1 Answer link Related questions How do you solve absolute value inequalities? When is a solution "all real numbers" when solving absolute value inequalities? How do you solve |a+1|\le 4? How do you solve |-6t+3|+9 \ge 18? How do you graph |7x| \ge 21? Are all absolute value inequalities going to turn into compound inequalities? How do you solve for x given |\frac{2x}{7}+9 | > frac{5}{7}? How do you solve abs(2x-3)<=4? How do you solve abs(2-x)>abs(x+1)? How do you solve this absolute-value inequality 6abs(2x + 5 )> 66? See all questions in Absolute Value Inequalities Impact of this question 1578 views around the world You can reuse this answer Creative Commons License