# How do you solve abs(2x+9)>17 ?

May 10, 2015

Given $\left\mid 2 x + 9 \right\mid > 17$
then
Either (Case 1) $\left(2 x + 9\right) < - 17$
or (Case 2) $\left(2 x + 9\right) > 17$

Case 1: $2 x + 9 < - 17$
$2 x < - 26$
$x < - 13$

Case 2: $2 x + 9 > 17$
$2 x > 8$
$x > 4$

Solution:
$x < - 13$ or $x > 4$