How do you solve $abs(2x+9)>17$ ?

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Answer 1 · 2015-05-10T20:53:21

Given $abs(2x+9)>17$
then
Either (Case 1) $(2x+9)<-17$
or (Case 2) $(2x+9)>17$

Case 1: $2x+9<-17$
$2x<-26$
$x<-13$

Case 2: $2x+9>17$
$2x>8$
$x>4$

Solution:
$x<-13$ or $x>4$

How do you solve abs(2x+9)>17 abs(2x+9)>17 ?