# How do you solve abs(4n-12)>16?

Solution : $n > 7 \mathmr{and} n < - 1$ In interval notation $\left(- \infty , - 1\right) \cup \left(7 , \infty\right)$
$| 4 n - 12 | > 16 \therefore 4 n - 12 > 16 \mathmr{and} 4 n > 28 \mathmr{and} n > 7$ OR $4 n - 12 < - 16 \mathmr{and} 4 n < - 4 \mathmr{and} n < - 1 \therefore$Solution: $n > 7 \mathmr{and} n < - 1$ In interval notation $\left(- \infty , - 1\right) \cup \left(7 , \infty\right)$[Ans]