How do you solve #abs(5x-15)-4>=21#?
1 Answer
Mar 25, 2018
Explanation:
#"inequalities of the type "|x|>=a#
#"Always have solutions of the form"#
#x <=-a" or "x>=a#
#rArr|5x-15|-4>=21#
#"add 4 to both sides"#
#rArr|5x-15|>=25#
#rArr5x-15<=-25" or "5x-15>=25#
#"add 15 to both sides in both inequalities"#
#rArr5x<=-10" or "5x>=40#
#"divide both sides in both inequalities by 5"#
#rArrx <=-2" or "x>=8larrcolor(blue)"solution"#
#(-oo,-2]uu[8,+oo)larrcolor(blue)"in interval notation"#
