How do you solve #abs(x-2)< 5#?

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Answer 1 · 2015-07-04T06:34:26

Clear the absolute value according to the pattern #absx< a=-a < x < a#. Then solve for #x#.

#abs(x-2)<5#

Clear the absolute value according to the pattern #absx< a=-a < x < a#.

#-5 < x-2 <5#

Solve for #x#.

Add 2 to all three terms.

#-5+2 < x-2+2 <5+2# =

#-3 < x <7#