# How do you solve abs(x-3)>2?

Apr 21, 2015

$x < 1$ or $x > 5$

Solution

$\left\mid x - 3 \right\mid > 2$
There are two possibilities:
$x - 3 < - 2$ or $x - 3 > 2$

$x - 3 + 3 < - 2 + 3$ or $x - 3 + 3 > 2 + 3$

$x < 1$ or $x > 5$