How do you solve #abs(x-3)> 5#?
2 Answers
Jun 14, 2015
x > 8 or x < -2
Explanation:
I x-3 I must be zero or positive
Consider I x - 3 I = 5
In this case x = 8 or x = -2
Now think about numbers either side of 8 and -2
If necessary substitute 7, 9 and -3 ,-1 into the original expression to see which side of 8 and -2 you need to be.
Jun 14, 2015
Solve |x - 3| > 5
Explanation:
Separate solving in 2 cases:
a. x - 3 > 5 -->
b. -(x - 3) = -x + 3 > 5 -> x < 3 - 5 -->
Graph:
==========|-2------|0-----------------|8=============