How do you solve #abs(x+5)>1#?

2 Answers
Oct 12, 2017

Answer:

#x<-6" or "x> -4#

Explanation:

#"inequalities of the type "|x|>a#

#"always have solutions of the form"#

#x< -a" or "x>a#

#rArrx+5< -1" or "x+5>1#

#rArrx< -6" or "x> -4" is the solution"#

#"the solution can be expressed in interval notation"#

#rArr(-oo,-6)uu(-4,+oo)#

Oct 12, 2017

Answer:

Solution: # x < -6 and x > -4 or (-oo,-6)uu(-4,oo)#

Explanation:

#|x+5| > 1 or x+5 > 1 or x >1-5 or x > -4 # OR

#|x+5| > 1 or x+5 < -1 or x < -1-5 or x < -6 #

Solution: # x < -6 and x > -4 or (-oo,-6)uu(-4,oo)# [Ans]