Question

How do you solve `abs(x+5)>1`?

Answer 1

`x<-6" or "x> -4`

Explanation:

`"inequalities of the type "|x|>a`

`"always have solutions of the form"`

`x< -a" or "x>a`

`rArrx+5< -1" or "x+5>1`

`rArrx< -6" or "x> -4" is the solution"`

`"the solution can be expressed in interval notation"`

`rArr(-oo,-6)uu(-4,+oo)`

Answer 2

Solution: `x < -6 and x > -4 or (-oo,-6)uu(-4,oo)`

Explanation:

`|x+5| > 1 or x+5 > 1 or x >1-5 or x > -4` OR

`|x+5| > 1 or x+5 < -1 or x < -1-5 or x < -6`

Solution: `x < -6 and x > -4 or (-oo,-6)uu(-4,oo)` [Ans]