# How do you solve abs(x+5)>12?

$x > 7 \mathmr{and} x < - 17$; In interval notation, solution is $\left(- \infty , - 17\right) \cup \left(7 , \infty\right)$
$| x + 5 | > 12 \therefore x + 5 > 12 \mathmr{and} x > 7$ OR
$| x + 5 | > 12 \therefore x + 5 < - 12 \mathmr{and} x < - 17$
In interval notation, solution is $\left(- \infty , - 17\right) \cup \left(7 , \infty\right)$[Ans]