Question

How do you solve `abs(x+5)>12`?

Answer 1

`x>7 or x<-17`; In interval notation, solution is `(-oo,-17)uu(7,oo)`

Explanation:

`|x+5|>12:.x+5>12 or x>7` OR
`|x+5|>12:.x+5<-12 or x<-17`
In interval notation, solution is `(-oo,-17)uu(7,oo)`[Ans]