How do you solve absx >=3|x|≥3? Algebra Linear Inequalities and Absolute Value Absolute Value Inequalities 1 Answer Evan Apr 20, 2018 x<=-3 or x>=3x≤−3orx≥3 Explanation: |x|>=3|x|≥3 Since xx can be positive or negative, -x>=3−x≥3 x<=-3x≤−3 or x>=3x≥3 Hence, x<=-3 or x>=3x≤−3orx≥3 Answer link Related questions How do you solve absolute value inequalities? When is a solution "all real numbers" when solving absolute value inequalities? How do you solve |a+1|\le 4|a+1|≤4? How do you solve |-6t+3|+9 \ge 18|−6t+3|+9≥18? How do you graph |7x| \ge 21|7x|≥21? Are all absolute value inequalities going to turn into compound inequalities? How do you solve for x given |\frac{2x}{7}+9 | > frac{5}{7}∣∣∣2x7+9∣∣∣>57? How do you solve abs(2x-3)<=4|2x−3|≤4? How do you solve abs(2-x)>abs(x+1)|2−x|>|x+1|? How do you solve this absolute-value inequality 6abs(2x + 5 )> 666|2x+5|>66? See all questions in Absolute Value Inequalities Impact of this question 1637 views around the world You can reuse this answer Creative Commons License