How do you solve and check #4x + 7( x - 8) = 4( x - 7)#?

1 Answer
Dec 18, 2016

#x=4#

Explanation:

To solve the equation, distribute the brackets, collect terms in x on the left side and numeric values on the right side.

distributing brackets.

#4x+7x-56=4x-28#

#rArr11x-56=4x-28#

collecting terms.

subtract 4x from both sides.

#11x-4x-56=cancel(4x)cancel(-4x)-28#

#rArr7x-56=-28#

add 56 to both sides.

#7xcancel(-56)cancel(+56)=-28+56#

#rArr7x=28#

To solve for x, divide both sides by 7

#(cancel(7) x)/cancel(7)=28/7#

#rArrx=4" is the solution"#

#color(red)"As a check"#

If x = 4 is a solution then the equation should be TRUE, that is both sides should be equal.
To test this, substitute x = 4 into the equation and evaluate.

#rArr"left side" =(4xx4)+7(4-8)=16-28=-12#

#"right side " =4(4-7)=4xx-3=-12#

Since both sides are equal then the equation is satisfied and hence x = 4 is the solution.