How do you solve and check #4x + 7( x - 8) = 4( x - 7)#?
1 Answer
Explanation:
To solve the equation, distribute the brackets, collect terms in x on the left side and numeric values on the right side.
distributing brackets.
#4x+7x-56=4x-28#
#rArr11x-56=4x-28# collecting terms.
subtract 4x from both sides.
#11x-4x-56=cancel(4x)cancel(-4x)-28#
#rArr7x-56=-28# add 56 to both sides.
#7xcancel(-56)cancel(+56)=-28+56#
#rArr7x=28# To solve for x, divide both sides by 7
#(cancel(7) x)/cancel(7)=28/7#
#rArrx=4" is the solution"#
#color(red)"As a check"# If x = 4 is a solution then the equation should be TRUE, that is both sides should be equal.
To test this, substitute x = 4 into the equation and evaluate.
#rArr"left side" =(4xx4)+7(4-8)=16-28=-12#
#"right side " =4(4-7)=4xx-3=-12# Since both sides are equal then the equation is satisfied and hence x = 4 is the solution.