How do you solve and check #5(x-2) + (-9) = -7(1-x)#?

1 Answer
Jim G.
Mar 4, 2017

#x=-6#

Explanation:

distribute the brackets on both sides of the equation.

#rArr5x-10-9=-7+7x#

simplifying gives.

#5x-19=-7+7x#

collect terms in x, on the left side and numeric values on the right side.

subtract 7x from both sides.

#5x-7x-19=-7cancel(+7x)cancel(-7x)#

#rArr-2x-19=-7#

add 19 to both sides.

#-2xcancel(-19)cancel(+19)=-7+19#

#rArr-2x=12#

divide both sides by - 2

#(cancel(-2) x)/cancel(-2)=12/(-2)#

#rArrx=-6#

To check that x = - 6 is the solution, substitute this value into the equation and if the left side equals the right side then it is the solution.

#color(blue)"As a check"#

#"left side "=5(-6-2)-9=(5xx-8)-9=-40-9=-49#

#"right side "=-7(1-(-6))=(-7xx7)=-49#

#rArrx=-6" is the solution"#

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