How do you solve and check your solution given #3 3/4+n=6 5/8#?

1 Answer
Apr 11, 2017

Answer:

#n=23/8=2 7/8#

Explanation:

First it would be useful to turn your fractions into improper fractions. This is so you can add and subtract them easily.

#" "3 3/4+n=6 5/8#

#[1]" "15/4+n=53/8#

Now your goal is to only have #n# on one side. We will do this by subtracting #15/4# from both sides.

#[2]" "15/4+n-15/4=53/8-15/4#

You may cancel #15/4# on the right side now, since #15/4-15/4=0#.

#[3]" "n=53/8-15/4#

You can simplify this further by combining #53/8# and #15/4#. But you will first need to make sure they have the same denominator. So multiply #15/4# by #2/2#. This is valid because #2/2=1#. Once you do this, both fractions will now have the same denominator.

#[4]" "n=53/8-(15/4)(2/2)#

#[5]" "n=53/8-30/8#

#[6]" "n=(53-30)/8#

#[7]" "color(blue)(n=23/8=2 7/8)#