Question

How do you solve and check your solution given `y+1 1/3=3 1/18`?

Answer 1

You first want to get `y` to one side, and the numbers to the other.

Explanation:

Subtract `1 1/3` from both sides:

`y+cancel(1 1/3)-cancel(1 1/3)=3 1/18-1 1/3`

To work this, we have to multiply the `1/3` by 1 disguised as `6/6`:

`y=3+1/18-1-(1/3xx6/6)`

`y=3-1+1/18-6/18=2-5/18`; we split the `2`

`y=(1+18/18)-5/18=1+13/18=1 13/18`