# How do you solve and check your solution given y+1 1/3=3 1/18?

Feb 10, 2017

You first want to get $y$ to one side, and the numbers to the other.

#### Explanation:

Subtract $1 \frac{1}{3}$ from both sides:

$y + \cancel{1 \frac{1}{3}} - \cancel{1 \frac{1}{3}} = 3 \frac{1}{18} - 1 \frac{1}{3}$

To work this, we have to multiply the $\frac{1}{3}$ by 1 disguised as $\frac{6}{6}$:

$y = 3 + \frac{1}{18} - 1 - \left(\frac{1}{3} \times \frac{6}{6}\right)$

$y = 3 - 1 + \frac{1}{18} - \frac{6}{18} = 2 - \frac{5}{18}$; we split the $2$

$y = \left(1 + \frac{18}{18}\right) - \frac{5}{18} = 1 + \frac{13}{18} = 1 \frac{13}{18}$