How do you solve and check your solutions to #-4/3=2/3z#?

1 Answer
Dec 21, 2016

Answer:

#z = -2#

Explanation:

First, I would multiply each side of the equation by #3# to eliminate the fraction and keep the equation balanced. This will make the equation easier to work with:

#3 xx -4/3 = 3 xx 2/3z#

#-(3 xx 4)/3 = (3 xx 2)/3z#

#-(color(red)(cancel(color(black)(3))) xx 4)/color(red)(cancel(color(black)(3))) = (color(red)(cancel(color(black)(3))) xx 2)/color(red)(cancel(color(black)(3)))z#

#-4 = 2z#

Now. we can solve for #z# while keeping the equation balanced:

#-4/color(red)(2) = (2x)/color(red)(2)#

#-2 = (color(red)(cancel(color(black)(2)))z)/color(red)(cancel(color(black)(2)))#

#-2 = z# or #z = -2#