# How do you solve and graph #abs(2x+3)<=11#?

##### 1 Answer

#### Explanation:

When solving an absolute value linear inequality of the form

Where SIGN is one of

first consider whether k > 0, k = 0, or k < 0.

k > 0 is the "normal case."

In such cases,

yield disjoint intervals as their solutions, and

In such cases,

yield single open or closed intervals.

The answer to your question will be a single closed interval.

You may solve these two inequalities separately for x.

Some textbooks will write an "and" situation as a "three-sided" inequality:

Subtract 3 and then divide by 2.

Leaving the steps to you, the solution is

On a number line put two filled-in dots: one at -7 and the other at 4. Shade in between.