# How do you solve and graph #abs(a-5)<3#?

##### 1 Answer

Mar 16, 2017

#### Answer:

#### Explanation:

The standard form for

#|x| < a # is.

#-a < x < a# This is used in the question here.

#rArr-3 < a-5 < 3# Isolate a in the centre interval by adding 5 to ALL 3 intervals.

#rArr-3+5 < acancel(-5)cancel(+5) < 3+5#

#rArr2 < a < 8larr" is the solution"#

To show the solution on a number line place

The solution is the values

#color(blue)"between"# 2 and 8 which is denoted by a heavy line drawn between the 2 open circles.