Question

How do you solve and graph `abs(k-4)>3`?

Answer 1

`k<1` or `k>7`

Explanation:

`abs(k-4)>3`
when does `abs(k-4)=3`?
`abs(k-4)=3 iff k-4=3 or k-4=-3 iff k=7 or k=1`

Now let's check what happens:
when `k<1`
`abs(0-4)=4>3`
when `k>7`
`abs(10-4)=6>3`
when `1>k>7`
`abs(5-4)=1<3`

so we need `k<1` or `k>7`