How do you solve and graph #t+17>=1#?

1 Answer
Jul 1, 2018

Answer:

See below:

Explanation:

Let's isolate #t# by subtracting #17# from both sides. We will get

#t>=-16#

This means all values of #t# that are greater than or equal to #-16# are in our solution set.

To graph this, we draw a closed circle at #t=-16#, because this is in our solution set. We now can draw an arrow pointing to the right, which represents values of #t# greater than #-16#.

Hope this helps!