How do you solve and graph # x + 3 ≥ 1 #?

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Answer 1 · 2017-09-04T15:23:40

See a solution process below:

Subtract #color(red)(3) from each side of the inequality to solve for #x# while keeping the inequality balanced:

#x + 3 - color(red)(3) >= 1 - color(red)(3)#

#x + 0 >= -2#

#x >= -2#

To graph this we will draw a vertical line at #-2# on the horizontal axis.

The line will be a solid line because the inequality operator contains an "or equal to" clause.

We will shade to the right side of the line because the inequality operator also contains a "greater than" clause:

graph{x>=-2}