How do you solve and write the following in interval notation: #| 4x | > -12#?

1 Answer
Oct 2, 2017

Answer:

#(-3 , 3)#

Explanation:

To solve inequalities involing absolute values we need to solve for the case when the value in the absolute bars is both a positive value and a negative value. We can do this as follows:

If: #|4x| > -12# and #|-(4x)|> -12#

Remove bars:

#4x > -12 => x > -3#

#-4x > -12 => x< 3#

In interval notation this is:

#(-3 , 3)#