How do you solve and write the following in interval notation: abs(5r + 2)< 18?

$r < \frac{16}{5} \mathmr{and} r > - 4$ In interval notation: $\left(- 4 , \frac{16}{5}\right)$
$| 5 r + 2 | < 18 \therefore 5 r + 2 < 18 \mathmr{and} 5 r + 2 > - 18 \mathmr{and} 5 r < 16 \mathmr{and} 5 r > - 20 \mathmr{and} r < \frac{16}{5} \mathmr{and} r > - 4 \therefore - 4 < r < \frac{16}{5}$ In interval notation: $\left(- 4 , \frac{16}{5}\right)$[Ans]