How do you solve and write the following in interval notation: #abs(5r + 2)< 18#? Algebra Linear Inequalities and Absolute Value Absolute Value Inequalities 1 Answer Binayaka C. Jul 25, 2016 #r<16/5 and r> -4# In interval notation: #(-4,16/5)# Explanation: #|5r+2| <18 :. 5r+2 <18 and 5r+2 > -18 or 5r<16 and 5r > -20 or r<16/5 and r > -4 :. -4 < r <16/5# In interval notation: #(-4,16/5)#[Ans] Answer link Related questions How do you solve absolute value inequalities? When is a solution "all real numbers" when solving absolute value inequalities? How do you solve #|a+1|\le 4#? How do you solve #|-6t+3|+9 \ge 18#? How do you graph #|7x| \ge 21#? Are all absolute value inequalities going to turn into compound inequalities? How do you solve for x given #|\frac{2x}{7}+9 | > frac{5}{7}#? How do you solve #abs(2x-3)<=4#? How do you solve #abs(2-x)>abs(x+1)#? How do you solve this absolute-value inequality #6abs(2x + 5 )> 66#? See all questions in Absolute Value Inequalities Impact of this question 1320 views around the world You can reuse this answer Creative Commons License