# How do you solve and write the following in interval notation: |x + 8| ≥ 2?

Jun 29, 2016

$x \le - 10$
$x \ge - 6$

#### Explanation:

$I x + 8 I \ge 2$
Solve the inequality in 2 parts:
a. $\left(x + 8\right) \ge 2$
$x \ge 2 - 8 - \to$x >= -6 b. -(x + 8) >= 2 - x - 8 >= 2 - x > 10$- \to$x <= -10#
Solution set expressed by intervals:
(-inf., -10] and [-6, inf.)
Note. The 2 end points are included in the solution set
Graph

=========== -10------------ -6=========== 0===============