How do you solve #b+ 3b = - 14+ b + 4- 2#?

1 Answer
Jim G.
Nov 19, 2016

#b=-4#

Explanation:

Start by simplifying both sides of the equation. That is collect like terms.

#rArr4b=b-12#

subtract b from both sides.

#4b-b=cancel(b)cancel(-b)-12#

#rArr3b=-12#

To solve for b, divide both sides by 3

#(cancel(3) b)/cancel(3)=(-12)/3#

#rArrb=-4" is the solution"#

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