# How do you solve by substitution 11y-3x=18 and -3=-16y+33?

Mar 29, 2018

From the second equation calculate y and put it in the second equation.

#### Explanation:

$- 3 = - 16 y + 33$
$16 y = 36$
$y = \frac{9}{4}$

$11 y - 3 x = 18$
$11 \cdot \left(\frac{9}{4}\right) - 3 x = 18$
$- 3 x = 18 - \frac{99}{4} = - \frac{27}{4}$
$x = \frac{9}{4}$