How do you solve by substitution $x - 2 y = - 1$ $x - 2y = -1$ and $2 x - y = 4$ $2x - y = 4$ ?

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How do you solve by substitution $x - 2 y = - 1$ $x - 2y = -1$ and $2 x - y = 4$ $2x - y = 4$ ?

1 Answer

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Answer 1 · 2015-06-10T09:58:11

The solution for the system of equations is
$x = 3, y = 2$ $color(blue)(x = 3 , y =2$

Explanation:

$x - 2 y = - 1$ $x - 2y = -1$
$x = - 1 + 2 y$ $x =color(blue)( -1+2y$ ........equation $(1)$ $(1)$

$2 x - y = 4$ $2x - y = 4$ ............equation $(2)$ $(2)$

Substituting equation $1$ $1$ in $2$ $2$ to find $y$ $y$
$2 (- 1 + 2 y) - y = 4$ $2color(blue)((-1+2y)) - y = 4$
$- 2 + 4 y - y = 4$ $-2 +4y -y = 4$
$3 y = 6$ $3y =6$
$y = 2$ $color(blue)(y=2$

Substituting $y$ $y$ in equation $1$ $1$ to find $x$ $x$ :
$x = - 1 + 2 y$ $x = -1+2y$
$x = - 1 + 4$ $x = -1+4$
$x = 3$ $color(blue)(x = 3$

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How do you solve by substitution $x - 2 y = - 1$ $x - 2y = -1$ and $2 x - y = 4$ $2x - y = 4$ ?

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Explanation:

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How do you solve by substitution $x - 2 y = - 1$ $x - 2y = -1$ and $2 x - y = 4$ $2x - y = 4$ ?