How do you solve by substitution x=3-3yx=3−3y and 4y=x+114y=x+11?
1 Answer
Mar 8, 2018
Explanation:
x=3-3yto(1)x=3−3y→(1)
4y=x+11to(2)4y=x+11→(2)
"since equation "(1)" gives x in terms of y we can "color(blue)"substitute ""it directly into equation "(2)since equation (1) gives x in terms of y we can substitute it directly into equation (2)
4y=3-3y+114y=3−3y+11
"add 3y to both sides"add 3y to both sides
4y+3y=3cancel(-3y)cancel(-3y)+11
rArr7y=14
"divide both sides by 7"
(cancel(7) y)/cancel(7)=14/7
rArry=2
"substitute "y=2" into equation "(1)
x=3-(3xx2)=-3
"solution is "x=-3" and "y=2