# How do you solve by substitution x= y - 11 and x - 3y = 1?

x - 3y = 1 -> (y - 11) - 3y = 1 -> -2y = 12 -> $y = - 6$ --> $x = - 6 - 11 = - 17$.
$x - 3 y = 1 \to - 17 - \left(- 3 \left(6\right)\right) = - 17 + 18 = 1$OK.