Question

How do you solve by substitution `x+y=2` and `3x+2y=5`?

Answer 1

`x=1` & `y=1`

Explanation:

Given equations

`x+y=2\ ........(1)`

`3x+2y=5\ ........(2)`

Substituting `y=2-x` from (1) in (2) as follows

`3x+2(2-x)=5`

`3x+4-2x=5`

`x+4=5`

`x=1`

substituting `x=1` in (1), we get

`1+y=2`

`y=1`

Answer 2

Here

Explanation:

If `x+y=2`
`x=2-y`

Put this into the second equation:

`3times(2-y) + 2y =5`

`6 - 3y + 2y =5`

`6-5 = y`

`y=1`

Since `x+y=2`

`x=2-y = 2-1 =1`

Your solution:

`x=1` and `y=1`

Or `x=y=1`