Question

How do you solve `cos(x)(cos(x) -1)=0`?

Answer 1

`x=0+2kpi" or "x=pi+2kpi`

Explanation:

`(cosx)(cosx)-1=0" can be expressed as"`

`cos^2x=1`

`rArrcosx=+-1`

`cosx=+1rArrx=0+-2kpicolor(white)(x);kin ZZ`

`cosx=-1rArrx=pi+2kpicolor(white)(x);kin ZZ`