How do you solve #d^ { 2} + 27d = 0#?

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Answer 1 · 2018-04-19T08:13:29

#color(purple)(d = 0, -27#

#d^2 + 27d = 0#

#d * (d + 27) = 0#

#(d + 0 ) * (d + 27) = 0#

#"Roots are " d = 0, d = -27#

Answer 2 · 2018-04-19T08:16:22

#d=-27" or "d=0#

#"take out a "color(blue)"common factor "d#

#rArrd(d+27)=0#

#"equate each factor to zero and solve for d"#

#rArrd=0#

#d+27-0rArrd=-27#